Question:
write the range of f(x)=sin−1(x), in [0,2π] other than [-​π/2,π/2]
Answer:
The inverse of sin function is also defined with domains [3π/2, 5π/2], [-5π/2, -3π/2], etc. and the same range.
This is because sin function is bijection and therefore, invertible.
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